11y-y^2=40

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Solution for 11y-y^2=40 equation: 



11y-y^2=40

We move all terms to the left:

11y-y^2-(40)=0

We add all the numbers together, and all the variables

-1y^2+11y-40=0

a = -1; b = 11; c = -40;
Δ = b2-4ac
Δ = 112-4·(-1)·(-40)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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